Newton’s Second Law –Part I
1.
| Item | Mass( ) | |||
| Hanger | ||||
| Glider | ||||
| Small Weights | ||||
| Large Weights | ||||
Glider length : _________________
2. Print out the “tables” of measurement which are required in procedure 6 and 7.
3.Make measurement with total mass fixed:
Total mass(m+ma) =glider+ 4 small weights + hanger = __________
| Hanging mass ma ( ) | Mean Acceleration( ) | Error-SDOM( ) | 
| 5 (hanger’s) | ||
| (5+10) | ||
| (5+20) | ||
| (5+30) | 
Print out a graph of “ a vs. ma “ and compare the slope with “g/(m+ma)”.
4. Keeping ma fixed at 15 grams and varying m with the large weights gives the data.
| Total mass m+ma ( ) | Mean Acceleration( ) | Error-SDOM( ) | 
| (186+15) | ||
| (186+50+15) | ||
| (186+100+15) | ||
| (186+150+15) | 
Print out a graph of “ a vs. m+ma “ and “a vs. 1/(m+ ma)“.
Compare the slope of the graph “a vs. 1/(m+ ma)“ with the value “mag“.
The slope should be close to “mag“. mag=(15 g) x (9.8 m/s2)=147 g m/s2
5. Measurement of g on the inclined plane:
The thickness of metal block : (x)______________.
The distance between the support legs : (y) _______________.
The angle of the inclined plane sinΘ= (x/y) = ______________.
| Glider mass ( ) | Mean Acceleration a ( ) | g ( ) | 
| (186) | ||
| (186+50) | ||
| (186+100) | ||
| (186+150) | 
p.s g = a/sinΘ
6. Discuss your results as much as possible.
Extra Credit:
Try to answer the questions on p.31.
- Printed by Ben-Li Young